If there are N persons and N-1 options for the number of people with whom every person can shake hands, at least two people have shaken hands with an equal number of people.
A pigeon hole principle would be a counting argument that states "if you have n items to place into m n boxes, then there are at least two items in a single boxes."
Now, according to the question;
There are N persons at a party, some of whom have shaken hands and others who have not. When two people shake hands, it counts to both of them shaking hands with one person.
As a result, it is impossible to tell who initiated the greeting. Then there's the following proposal:
It is said that at least two individuals have shaken hands the same amount of individuals.
Thus,
Although you can shake hands to yourself, an individual can shake hands had between 0 and N-1 persons. That is N different options. If a person had shaken hands to everyone else, then no one has not touched hands with anyone. And the opposite is true.
As a result, the possibilities 0 and N-1 are mutually exclusive. So we're down to N-1 people with whom each individual can shake hands.
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