The volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.
The volume of a given mass of gas can be calculated using the following formula:
PV = nRT
Where;
According to this question, 0.98 moles of oxygen gas at 275 k contains a pressure of 2.0 atm. The volume is calculated as follows:
2 × V = 0.98 × 0.0821 × 275
2V = 22.13
V = 11.06L
Therefore, the volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.
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