A solution has a ph of 7.5 at 50∘c. what is the poh of the solution given that kw=8.48×10−14 at this temperature?

Respuesta :

The pOH value of solution will be  -5.54.

By calculating the concentration of OH ions in a solution, pOH can be used to gauge how acidic or alkaline a solution is. The OH ion concentration's negative logarithm would be known as pOH.

Given that:

pH = 7.5

kw = 8.48×[tex]10^{-14}[/tex]

pH = - log [[tex]H^{+}[/tex]]

[[tex]H^{+}[/tex]] = [tex]10^{-pH}[/tex]

Put the value of pH in above equation.

[[tex]H^{+}[/tex]]  = [tex]10^{-7.5}[/tex]

[[tex]H^{+}[/tex]] = 3.16 × [tex]10^{-8}[/tex]

Put the value of given data in above equation.

[[tex]OH^{-}[/tex]] =Kw / [tex][H^{+} ][/tex]

[[tex]OH^{-}[/tex]]  =  8.48×[tex]10^{-14}[/tex] /  3.16 × [tex]10^{-8}[/tex]

[[tex]OH^{-}[/tex]] = 2.6 × [tex]10^{-6}[/tex].

pOH  = -log [[tex]OH^{-}[/tex]]

pOH = =log [ 2.6 × [tex]10^{-6}[/tex]]

pOH = log [2.9] - 6log 10

pOH = 0.46 -6

pOH = -5.54

Therefore, the pOH value will be -5.54

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