Sunil, Param and Vikas drive at
20 km/hr, 50 km/hr and 80 km/hr
respectively. Sunil starts from Point A for Point B. Param starts from Point A, 2 hours after Sunil starts and Vikas leaves some time after Param from Point A. Both Param and Vikas overtake Sunil at the same instant.
How many hours after Sunil does
Vikas leave Point A?
(a) 4.5 hours
(b) 4.0 hours
(c)
3.5 hours
(d) 2.5 hour

Respuesta :

The value of x = 5/3 and y = 1/4

Vikas leaves after 75 minutes of Sunil.

The correct option is (d) 2.5 hour.

How to simplify the value of x?

Let Param meet Sunil after x hr.

So, 20x = 50(x - 1)

simplifying the above equation we get

20x = 50x - 50

30x = 50

x = 50/30

The value of x = 5/3

x = (5/3) [tex]*[/tex] 60 = 100 minutes .

Let Vikas starts after y hr of Param.

[tex]$20 * \frac{5}{3}=80 *\left(\frac{5}{3}-1-y\right)$[/tex]

simplifying the above equation we get

[tex]$\frac{100}{3}=80 *\left(\frac{2}{3}-y\right)$[/tex]

[tex]$\frac{5}{3}=4 *\left(\frac{2}{3}-y\right)$[/tex]

5 = 4 [tex]*[/tex] (2 - 3y)

5 = 8 - 12 y

12y = 3

The value of y = 1/4

y = (1/4) [tex]*[/tex] 60 = 15 minutes

Vikas leave after (60 + 15) minutes = 75 minutes of Sunil.

Vikas leaves after 75 minutes of Sunil.

Hence, The correct option is (d) 2.5 hour.

To learn more about the value of x refer to:

https://brainly.com/question/11874663

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