The value of x = 5/3 and y = 1/4
Vikas leaves after 75 minutes of Sunil.
The correct option is (d) 2.5 hour.
Let Param meet Sunil after x hr.
So, 20x = 50(x - 1)
simplifying the above equation we get
20x = 50x - 50
30x = 50
x = 50/30
The value of x = 5/3
x = (5/3) [tex]*[/tex] 60 = 100 minutes .
Let Vikas starts after y hr of Param.
[tex]$20 * \frac{5}{3}=80 *\left(\frac{5}{3}-1-y\right)$[/tex]
simplifying the above equation we get
[tex]$\frac{100}{3}=80 *\left(\frac{2}{3}-y\right)$[/tex]
[tex]$\frac{5}{3}=4 *\left(\frac{2}{3}-y\right)$[/tex]
5 = 4 [tex]*[/tex] (2 - 3y)
5 = 8 - 12 y
12y = 3
The value of y = 1/4
y = (1/4) [tex]*[/tex] 60 = 15 minutes
Vikas leave after (60 + 15) minutes = 75 minutes of Sunil.
Vikas leaves after 75 minutes of Sunil.
Hence, The correct option is (d) 2.5 hour.
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