a = 8, b = 4, and c = 16
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Step-by-step explanation:
Greetings !
Firstly, plug in give values of the variables to the expression
[tex]( \frac{8}{4} ) {}^{2} - \frac{16}{8 - 4} [/tex]
apply exponent rule
[tex]( \frac{a}{b} ) {}^{c} = \frac{a {}^{c} }{b {}^{c} } [/tex]
[tex] \frac{8 {}^{2} }{4 {}^{2} } = \frac{64}{16} = 4[/tex]
Whereas for the second expression
[tex] \frac{16}{8 - 4} = \frac{16}{4} = 4 [/tex]
Thus, subtract the numbers
[tex]4 - 4 = 0[/tex]
Hope it helps!
Answer: 0
Step-by-step explanation:
To solve this problem, plug in. In other words, replace all of the letters with the given numbers. (this is also called substitution, I just described it this way to simplify it).
"a" becomes 8
"b" becomes 4
"c" becomes 16
PEMDAS= Parenthesis, Exponents,Division, Addition, Subtraction
(8/4)² - 16/8-4
2² - 16/8-4
4 - 16/8-4
4 - 16/4
4 - 4 = 0
Hope this helps!! :D
attachment, for reference: