From the calculation here, the length of C'B is given as 15.
We have the formula
d^2 = (x2 – x1)^2 + (y2 – y1)^2
This is the distance formula. This has a linear relationship with with the segments when we are to find the distance. If it is dilated by a scale of 3, the given distance between these two would also have to be dilated by 3.
From the diagram , we have these values where
C = (x1, y1) = (8, 10)
and also
B = (x2, y2) = (12, 13)
We have to put these values in the formula of the distance in order to get the distance
[tex]d^2= (12-8)^2 + (13-10)^2[/tex]
= 4² + 3²
= 16 + 9
= 25
d = √25
d = 5
C'B is by a scale factor of 3 hence we would have , 3 *5 = 15
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