2(f^4)^2f3 divided by 6f² is simplified to give 2/ 3 f^2
Given the expression;
2(f^4)^2f^3 divided by 6f^9
We have to expand the expression:
= [tex]\frac{2f^4 * 2f^3}{6f^9}[/tex]
Find the common factor, we get:
= [tex]\frac{2 * 2 }{6f^2}[/tex]
Multiply the numerator
= [tex]\frac{4}{6f^2}[/tex]
Let's divide through to get simpler terms
= [tex]\frac{2}{3f^2}[/tex]
= 2/ 3 f^2
Thus, 2(f^4)^2f^3 divided by 6f^9 is simplified to give 2/ 3 f^2
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