Find the distance between the two points in simplest radical form. (0,6)(9,-1)

Answer:
sqrt(130)
Step-by-step explanation:
distance formula
d^2 = (x1-x2)^2 + (y1-y2)^2 ( this is just Pythagorean theorem)
d^2 = ( 0-9)^2 = ( 6 - -1)^2
d^2 = 81 + 49
d = sqrt(130) = sqrt (5 * 2 * 13) so it is in simplest form
Answer:
[tex]\sf \sqrt{130} \quad is \ the \ distance \ between \ these \ two \ points[/tex]
Explanation:
Distance of two points is given by the formula:
[tex]\sf Distance = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \quad where\ (x_1, y_1), (x_2, y_2) \ are \ points[/tex]
Substituting the values in the equation
[tex]\sf d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
[tex]\sf d = \sqrt{(9- 0)^2 + (-1 -6)^2}[/tex]
[tex]\sf d = \sqrt{(9)^2 + (-7)^2}[/tex]
[tex]\sf d = \sqrt{81 + 49}[/tex]
[tex]\sf d = \sqrt{130}[/tex]