The statements that are true about the quadratic equation x² - 6x + 2 = 0 are;
The graph of the quadratic equation has a minimum value.
The extreme value is at the point (3,-7).
The solutions are; 3 ± √7.
How to Interpret Quadratic Graphs?
We have the quadratic equation, x² - 6x + 2 = 0
Let us find first derivative of the equation to get;
f'(x) = 2x - 6
At f'(x) = 0, we have;
2x - 6 = 0
x = 3
At x= 3, y = 3² - 6(3) + 2 = -7
Thus, the extreme value is at (3, -7)
Second derivative of the quadratic equation is given by;
f"(x) = 2
Second derivative is a positive value and as such the graph of the equation has a minimum value.
B using online quadratic equation calculator, we have the roots as;
x = 3 ± √7.
Read more about Quadratic Graphs at; https://brainly.com/question/14477557
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