Out of 400 people sampled, 280 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids.

Give your answers as decimals, to three places

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The confidence interval at 90% is given by 0.662 p < 0.738.

What is a confidence interval?

A confidence interval can be defined as a range of estimated values that defines the probability that a population parameter would fall or lie within it.

How to calculate value of the test statistic?

The test statistic of a population can be calculated by using this formula:

[tex]t=\frac{x\;-\;u}{\frac{\delta}{\sqrt{n} } }[/tex]

Where:

  • x is the sample mean.
  • u is the mean.
  • is the standard deviation.
  • n is the number of hours.

For the sample proportion, we have:

Sample proportion, P = 280/400

Sample proportion, P = 0.7.

The standard error of the sample is given by:

Standard error = √(0.7 × (1 - 0.7)/400)

Standard error = √(0.7 × (0.3)/400)

Standard error = √(0.000525)

Standard error = 0.0229.

Alpha, α = 1 - 90/100

Alpha, α = 1 - 0.9

Alpha, α = 0.1

Critical probability (p*) = 1 - α/2

Critical probability (p*) = 1 - 0.1/2

Critical probability (p*) = 0.95.

For the z-score, we have:

Zα/2 = 1.645.

Margin of error is given by:

Margin of error, E = 1.645 × 0.0229

Margin of error, E = 0.038.

Therefore, the confidence interval at 90% is given by:

p - E < p < p + E

0.7 - 0.038 < p < 0.7 + 0.038

0.662 p < 0.738.

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