The specific heat capacity of the metal would be 5387.460 J/kgC
It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
As given in the problem A 64.9g metal block is heated to a temperature of 99.9C in boiling water. The metal is transferred to a calorimeter containing 131g of isopropyl alcohol (specific heat capacity 2370J/kgC at 110C. The final temperature of the mixture is 25C.
Heat lost by the metal block = heat gain by the isopropyl alcohol
mCΔT for metal =mCΔT for isopropyl alcohol
where C is the respective specific heat capacity for metal as well as isopropyl alcohol
64.9 ×C×(99.9 -25) = 131× 2370×(110-25)
C = 5387.460 J/kgC
Thus, the specific heat capacity of the metal comes out to be 5387.460 J/kgC
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