The answer is [tex]26\frac{2}{3}[/tex]
8 copies of the sum of ([tex]\frac{4}{3}[/tex]) or 4 thirds and 2 more can be expressed as 8 x ( [tex]\frac{4}{3}[/tex] + 2 )
Therefore, you have:
8 x ([tex]\frac{4}{3}[/tex] + 2) (firstly, let solve the expression in bracket)
Therefore, you have
= ([tex]\frac{4}{3}[/tex] + 2) is same as [tex]\frac{4}{3}[/tex] + [tex]\frac{2}{1}[/tex]
= ([tex]\frac{4}{3}[/tex] + [tex]\frac{2}{1}[/tex]) / 3 (3 is the lowest common denominator, or the smallest number that can divide the denominator.
= [tex]\frac{4}{3}[/tex] + [tex]\frac{6}{3}[/tex]
= 4 + 6/3
= [tex]\frac{10}{3}[/tex]
Recall we have 8 copies of the sum,
Therefore,
= 8 x ([tex]\frac{10}{3}[/tex])
= 8 x 10/3
= [tex]\frac{80}{3}[/tex]
= [tex]26\frac{2}{3}[/tex]
Therefore, 8 copies of the sum of 4 thirds and 2 more is [tex]26\frac{2}{3}[/tex]
Notably, we used the rule of BODMAS to solve the question.
Significantly we derived the solution by using Bracket, multiplication and addition. It is also important to note that 4 thirds can be expressed as [tex]\frac{4}{3}[/tex].
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