Respuesta :

f(3) =  3^3 - 14*9 + 61*9 - 84 =  0

so 3 is one zero

long division of the expression by (x - 3)  gives the quadratic x^2 -11x + 28 which = (x - 7)(x-4)   so the other zeros are 4 and 7.

3,4 and 7 
calculista

Answer:

The zeros of the function are

[tex]7,4,3[/tex]

Step-by-step explanation:

we know that

The x-intercept  is the value of x when the value of the function is equal to zero.

The x-intercepts represents the zeros of the function

In this problem we have

[tex]f(x)=x^{3}-14x^{2} +61x-84[/tex]

Using a graphing tool

see the attached figure

The zeros of the function are

[tex]7,4,3[/tex]


Ver imagen calculista

Otras preguntas