at 25 degrees, the rate constant for the first order decomposition of a pesticide solution is 6.40 x 10^-2 min^-2. If the starting concentration of pesticide is 0.0314 M, what concentration will remain after 62.0 min at 25 degree Celsius?

The correct answer is 2.11 x 10^2 M, please show the steps.

If the initial amount is 1, the amount remaining at time t is exp(-rt), where r is the rate constant (.0064), and t is the time (62). The value of the exponential is 0.6725, and doing the obvious multiplication gives .0211 mole.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Answer Link

at 25 degrees, the rate constant for the first order decomposition of a pesticide solution is 6.40 x 10^-2 min^-2. If the starting concentration of pesticide is 0.0314 M, what concentration will remain after 62.0 min at 25 degree Celsius? The correct answer is 2.11 x 10^2 M, please show the steps.

Respuesta :

Otras preguntas

at 25 degrees, the rate constant for the first order decomposition of a pesticide solution is 6.40 x 10^-2 min^-2. If the starting concentration of pesticide is 0.0314 M, what concentration will remain after 62.0 min at 25 degree Celsius?

The correct answer is 2.11 x 10^2 M, please show the steps.