contestada

Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative 3. E is at 2, 4. 1.67 −1.33 0.75 −1.25

Respuesta :

The answer would be -1.25

Answer:

The correct option is 4.

Step-by-step explanation:

It is given that DF and EF form a 1:3 ratio. The coordinates of the end points of the segment DE are D(-3,-3) and E(2,4).

According to the section formula, if a point p divides a line in m:n, then the coordinates of p are

[tex](\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})[/tex]

y value for point F is calculated as

[tex]y=\frac{(1)y_2+(3)y_1}{1+3}[/tex]

The end points of the segment DE are D(-3,-3) and E(2,4).

[tex]y=\frac{(1)(4)+(3)(-3)}{4}[/tex]

[tex]y=\frac{4-9}{4}[/tex]

[tex]y=\frac{-5}{4}[/tex]

[tex]y=-1.25[/tex]

The y- value for point F is -1.25. Therefore the correct option is 4.