Factor –7x3 + 21x2 + 3x – 9 by grouping. What is the resulting expression?
(3 – 7x)(x2 – 3)

(7x – 3)(3 + x2)

(3 – 7x2)(x – 3)

(7x2 – 3)(3 + x)

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robertparise76 robertparise76 · Answer 1 · 2017-02-10T16:53:47+01:00

take the first 2 and take out -7x2. bringing it to (-7x2)(x-3)+(3x-9)
then take out 3 on the right side.
-7x^2 (x-3)+3 (x-3)
factors to (3-7x2)(x-3)

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aksnkj aksnkj · Answer 2 · 2022-01-25T12:42:44+01:00

The resulting expression for factor of [tex]-7x^3 + 21x^2 + 3x- 9[/tex] will be [tex](x-3)(3-7x^{2} )[/tex].

Given expression,

[tex]-7x^3 + 21x^2 + 3x- 9[/tex].

We have to factorize the above expression by grouping method.

In grouping method of factorization we make group of two and take out common term.

Now from [tex]-7x^3 + 21x^2 + 3x- 9[/tex].

Now taking out common term we get,

[tex]-7x^{2} (x-3)+3(x-3)[/tex]

Taking [tex](x-3)[/tex] common we get,

[tex](x-3)(-7x^{2} +3)[/tex]

[tex](x-3)(3-7x^{2} )[/tex].

Hence the correct option is C. [tex](x-3)(3-7x^{2} )[/tex].

For more details about factorization, follow the link:

https://brainly.com/question/13114757