Calculate the area of the figure below using the following information: Area of triangle ABC = 31.8 square units Area of triangle ACD = 39.2 square units Area of triangle AED = 35.5 square units Image of irregular pentagon with vertices points A, B, C, D, and E starting at upper left moving clockwise. Two dotted diagonal lines, one connecting vertices A and C, and the second connecting vertices A and D. The area of the Figure ABCDE is ______ square units. Answer for Blank 1:

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boffeemadrid boffeemadrid · Answer 1 · 2019-03-08T09:19:04+01:00

Answer:

Area of irregular pentagon=106.5 square units.

Step-by-step explanation:

It is given that Area of triangle ABC = 31.8 square units,

Area of triangle ACD = 39.2 square units and

Area of triangle AED = 35.5 square units.

Thus, ABCDE makes an irregular pentagon, therefore

Area of irregular pentagon= Area of triangle ABC +Area of triangle ACD+Area of triangle AED

⇒Area of irregular pentagon=31.8+39.2+35.5

⇒Area of irregular pentagon=106.5 square units.

Thus, area of an irregular pentagon is 106.5 square units.

roccokarr2020 roccokarr2020 · Answer 2 · 2021-08-11T22:38:03+02:00

Answer:

106.5

Step-by-step explanation:

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