Respuesta :
The percentage yield of Li₃N is 28.63 %.
6Li(s) + N₂ (g) → 2 Li₃N (s)
According to balanced reaction
6 x 6.94 g Li reacts with 28 g N₂
12.8 g Li reacts with 12.8 x 28 / 6 x 6.94 = 8.61 g N2
But we have 34.9 g N₂. so N₂ present in excess
Limiting reagent = Li
6 x 6.94 g Li gives 2 x 34.83 g Li₃N
12.8 g Li gives 12.8 x 2 x 34.83 / 6 x 6.94 = 21.41 g Li3N
Actual yield = 6.13 g
Theoretical yield = 21.41 g
% yield = (actual yield / theoretical yield) x 100
% yield = (6.13 / 21.41) x 100
% yield = 28.63 %
Percentage yield is the percentage ratio of real yield to the theoretical yield. It's miles calculated to be the experimental yield divided through theoretical yield increased by a 100%. If the actual and theoretical yield are the equal, the percent yield is one 100%.
Percentage yield is the range calculated indicating the difference in percentage among the theoretical yield and real yield of an experiment. Whilst experimenting with unique solutions or inside the manufacturing of chemical solutions you have got by means of-merchandise and the real meant products.
Learn more about Percentage yield here:- https://brainly.com/question/8638404
#SPJ9