Answer: #11? y^2-14 #12 m^2-64
Step-by-step explanation:
- Factor each of the binomials: (2y-5)^2 -> 2 (y-5) (y+5) and (y+6)^2 -> (y+6) (y-6)
- Multiply the each factored binomial into perfect squares: (since the second numbers are opposites it will be binomials since they cancel out) 2 (y-5) (y+5) would be 2y^2-10y+10y-50 or 2y^2-50 and (y+6) (y-6) will become y^2-6y+6y-36 or y^2-36
- Subtract the binomials: Remember when you are subtracting polynomials you are changed the sign to addition and invert the operations of the second polynomial (so if the term was positive it would be negative and vice versa) so it would be 2y^2-50 + ‐y^2+36 and that would equal y^2-14
- For the second question you apply the same steps to #12 to get m^2-64
