A possible solution for this case of collinear points is (x, AB, BC, CD, AC, AD) = (0, 18, 14, 10, 32, 42).
In this question we have four points that are collinear, that is, that lie on the same line. Mathematically, speaking we have the following equations representing the geometric system:
BC = 14 + x (1)
AD = 42 + x (2)
AC = x + 32 (3)
By (1) and (3):
AB = (x + 32) - (14 + x)
AB = 18
By (2) and (3):
CD = (42 + x) - (x + 32)
CD = 10
If x = 0, then BC, AD and AC are, respectively:
BC = 14, AD = 42, AC = 32
Then, a possible solution for this case of collinear points is (x, AB, BC, CD, AC, AD) = (0, 18, 14, 10, 32, 42).
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