The mass percent of ethylene glycol in a 1.81 M aqueous solution, whose density is 1.07 is 10.5%
First, we will calculate the mass of ethylene glycol in 1 L of the solution.
There are 1.81 moles of ethylene glycol per liter of solution.
The molar mass of ethylene glycol is 62.07 g/mol.
1 L Solution = (1.81/ 1L of solution) × (62.07/1 mol EG) = 112.3g EG
Now, we will calculate the mass of 1 L (1000 mL) of the solution, considering its density is 1.07 g/mL.
1000mL × 1.07/ mL = 1070g
There are 112.3 g of ethylene glycol in 1070 g of solution.
Therefore,The mass percent of ethylene glycol is:
%EG = 112.3g/ 1070g × 100 = 10.5 %
The mass percent of ethylene glycol in a 1.81 M aqueous solution, whose density is 1.07, is 10.5%.
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