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A boat moves through the water with two forces acting on it. One is a 1,725-N forward push by the water on the propeller, and the other is a 1,300-N resistive force due to
the water around the bow.
(a) What is the acceleration of the 1,400-kg boat?
0.30
m/s 2
(b) If it starts from rest, how far will the boat move in 20.0 s?
2
m
(c) What will its velocity be at the end of that time?
3
m/s

Respuesta :

bharathparasad577

The data given to us is as follows

Force of push on the boat= 1725N

Force of resistance on the propeller = 1300N

By Newton's law of motion,

Force is directly proportional to mass and acceleration of the body

F= ma

Mass of the boat is given to be 1400kg

Force of movement= Force of push - Force of resistence

                              = 1725N - 1300N

                               =425N

F = ma

425 = 1400 x a

a = 425 /1400 = 0.3035 m/s^2

(b) it is given that boat starts from rest

 u =0

 a=0.303 m/s^2

 Using the formula

S= ut +1/2 at^2

S= 0 + 1/2 x 0.303 x 20x20

  = 60.6m

(c) Velocity at t=20s

 v=u+at

 v = 0 + 0.303 x 20

    6.06m/s

Disclaimer:

Question has some incomplete and unused mentions

#SPJ9

   

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