(a) The force the spring exert on glider A is 1.88 N.
(b) The force the spring exert on glider B is 2.82 N.
Acceleration of the spring
The acceleration of the spring is calculated as follows;
F = ma
a = F/m
a = 5.4 N / (0.15 kg + 0.4 kg + 0.6 kg0
a = 4.7 m/s²
force the spring exert on glider A
F(A) = ma
F(A) = 0.4 kg x 4.7 m/s²
F(A) = 1.88 N
force the spring exert on glider B
F(B) = 0.6 kg x 4.7 m/s²
F(B) = 1.88 N
F(B) = 2.82 N
Thus, the force the spring exert on glider A is 1.88 N.
The force the spring exert on glider B is 2.82 N.
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