The question has two parts
beginning with part 1:
R1 and R2 are in series
R3 and R4 are in series with each other
R5 and R6 are in series with each other
R3 and R4 are parallel to R5 and R6
it is given that R1=R2=R3=R4 =2 Ohm
R5=R7=1 Ohm
R6 = 3ohm
We know that resistance is the sum of resistances in series and reciprocal sum of resistances in parallel
R1+R2=2+2=4 ohm
R3+R4 = 2+2 = 4ohm
R5+R6 =1+3=4Ohm
R3 and R4 and R5 and r6 are in parallel = 4 x 4/4+4 = 16/8 = 2 ohm
Resultant resistance = 4 + 2 +1 =7 phms
In part 2 of the question,
R1=R7=2 ohm
R2=R3=R6 =1 ohm
R4=R5=3 ohm
R2,R3 are in series, R5 and R6 are in series
R2,R3 AND R4 and R5 ,R6 in parallel
R2+R3 = 1+1 =2 ohm
R5 +R6 = 3+1 =4 ohm
R2,R3 AND R4 and R5 ,R6 in parallel= 1/(1/2+1/4+1/3 )=v 1/(6+3+4)/12
=12/13
Resultant resistance = 2+2+12/13 =4.93 ohm
#SPJ9
