If 7.50 mol of NH₃ and 8.15 mol of O₂ react in the following reaction. The number of moles of H₂O that will be formed is 9.84 moles.
The mole is a SI unit of measurement that is used to calculate the quantity of any substance.
Using the molar coefficients in the balanced equation, 6 moles of water are formed for every 4 moles of NH₃.
6 moles of water are formed for every 5 moles of O₂.
So (7.5 moles NH₃)(6 moles H₂O)/4 moles NH₃) = 11.25 moles water
For (8.20 moles O₂) / (6 moles H₂O)(5 moles O₂) = 9.84 moles H₂O.
So O₂ is the limiting reagent, and we can only make as much product as allowed by the limiting reagent.
Thus, the number of moles is 9.84 moles of water.
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