Answer:
[tex]y=18x+ 12[/tex]
Step-by-step explanation:
Given equation:
[tex]2+\dfrac{1}{6}y=3x+4[/tex]
Solve for y
Subtract 2 from both sides:
[tex]\implies 2+\dfrac{1}{6}y-2=3x+4-2[/tex]
[tex]\implies \dfrac{1}{6}y=3x+2[/tex]
Multiply both sides by 6:
[tex]\implies 6 \cdot \dfrac{1}{6}y= 6 \cdot3x+ 6 \cdot2[/tex]
[tex]\implies y=18x+ 12[/tex]
