You wish to prepare 189 grams of 5.70 % solution.

You will need _____ grams of sodium acetate and ____ mL of water.

Assume that the density of water is 1.00 g/mL.

Respuesta :

You will need 10.773 grams of sodium acetate and 178.23  mL of water.

What is a solution?

A solution is a homogenous mixture of a solute and a solvent. When two substance mixes perfectly together makes a solution.

Given, that the density of water is 1.00 g/mL.

Preparation of 189 grams of 5.70 % solution.

Mass of CH₃COONa

189 x  5.70 / 100 = 10.773 grams

Mass of water = mass of solution – mass of solute

189 - 10.77 = 178.23 grams

Volume = mass / density

178.23 / 1.00 = 178.23  ml

Thus, the mass of sodium acetate is 10.773 grams, and the volume of water is 178.23  ml.

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