The resistance in the LED, CFL, and incandescent lightbulb would be 2.50 ohms.
Resistance is the obstruction of electrons in an electrically conducting material.
As given in the problem On three separate instances you connect each lightbulb to a battery with an and of 12.00V and an internal resistance of 0.5. When a current of 4A passes through the battery,
resistance = voltage /current
= 12 volt/4 ampere
= 3 Ohm
The total resistance across the circuit = internal resistance + resistance across the bult
resistance across the bulb = 3 - .50
=2.5 Ohms
Thus, the resistance in the LED, CFL, and incandescent lightbulb would be 2.50 ohms
To learn more about resistance, refer to the link;
brainly.com/question/14547003
#SPJ1
