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A stone dropped from a cliff hits the ground 3.00 s later. Find (a) the speed with which the stone hits the ground, and (b) the distance it fell.

Respuesta :

(a) The speed as the stone hits the ground is 29.4 m/s (b) The distance at which the stone fell is 44.1 m.

What is speed?

Speed can be defined as the ratio of distance to time.

(a) To calculate the speed at which the stone hit the ground, we use the formula below.

Formula:

  • v = u+gt............ Equation 1

Where:

  • v = Final speed of the stone
  • u = Initial speed of the stone = 0 m/s
  • t = time = 3 seconds
  • g = acceleration due to gravity = 9.8 m/s²

Substitute the values above into equation 1

  • v = 0+3×9.8
  • v = 29.4 m/s

(b) To calculate the distance the stone fell, we use the formula below.

  • S = ut+gt²/2........... Equation 2

Where:

  • S = Distance

Solving for S by substituting into equation 2

  • S = (0×3)+(9.8×3²)/2
  • S = 44.1 m

Hence, (a) The speed as the stone hits the ground is 29.4 m/s (b) The distance at which the stone fell is 44.1 m.

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