The four consecutive integers are 121, 122, 123, 124.
We have the sum of four consecutive equals to 490
We have to determine those integers.
An integer is a number with no decimal or fractional part and it includes negative and positive numbers, including zero.
Assume the first integer is x. Then, the other integers will be -
x + 1, x + 2, x + 3.
Therefore -
x + (x + 1) + (x + 2) + (x + 3) = 490
4x + 6 = 490
4x = 484
x = 121
So -
x = 121
x + 1 = 122
x + 2 = 123
x + 3 = 124
Hence, the four consecutive integers are 121, 122, 123, 124.
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