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what do i do when my algebra has something like this 9x+45=15x+3/7x im used to having constants and variables on both sides​

Respuesta :

s157778

Answer:

x = 2 11/12

Step-by-step explanation:

First of all, on the right you have to combine 15x+3/7x which equals 15 3/7x.

9x + 45 = 15 3/7x

-9x              -9x             Next step is to subtract 9x from both sides.

45 = 15 3/7x

/              /

15 3/7   15 3/7        Third step is to divide 15 3/7 on both sides to leave x          

                              by itself.

35/12 = 2 11/12 = x

x = 2 11/12

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