Divide.3 y-12 / 2y+4 ÷ 6y-24 / 8+4 y
How to divide the given expression 3 y-12 / 2y+4 ÷ 6y-24 / 8+4 y?
[tex]\frac{3y-12}{2y+4}*\frac{8+4y}{6y-24} \\\\\frac{3y-12}{2y+4}*\frac{2(4+2y)}{2(3y-12)} \\\\\frac{2}{2} =1[/tex]
What are the restrictions on the variables?
If y=4 ⇒demoninator(6*4-24) =0 = ∞
Similarly,If y= -2 ⇒demoninator((2*-2)+4) =0 = ∞
So, y≠4, y≠-2
How to find restrictions on the variables?
To learn more about restrictions on the variables, refer:
brainly.com/question/10957518
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