Respuesta :
The 10th term of the given arithmetic sequence 2,8,14,20, ........... is ( a₁₀ = 56.)
Describe the AP arithmetic progression series?
The difference between two mathematical orders is a fixed value in Arithmetic Progression (AP). Arithmetic Sequence is another term for it.
We'd come across a few key words in AP which have been classified as:
- The first term (a)
- Common difference (d)
- Term nth (an)
- The total of first n terms (Sn)
The AP can also be viewed in terms of common differences, as illustrated below.
- The following is the process for evaluating an AP's n-th term: an = a + (n − 1) × d
- The so these is the arithmetic progression sum: Sn = n/2[2a + (n − 1) × d].
- Common difference 'd' of an AP: d = a2 - a1 = a3 - a2 = a4 - a3 = ...... = an - an-1.
Now, the sequence given in the question is; 2,8,14,20, ...........
Define the first term as 'a₁' = 2.
Define 'a₂' = 8 is the second term.
Define the third term as 'a₃' = 14.
Evaluate the common difference;
d = a₂ - a₁
Put the values in the obtained equation;
d = 8 - 2 = 6
Now, to evaluate the value of the 10th term imply the formula of nth term.
an = a + (n − 1) × d , n = total number of terms = 10.
Substitute all the values;
a₁₀ = 2 + (10 - 1) × 6
a₁₀ = 2 + 9 × 6
a₁₀ = 2 + 54
a₁₀ = 56.
Therefore, the value of the 10th term is found as a₁₀ = 56.
To know more about the arithmetic progression, here
brainly.com/question/24191546
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