The total number of seats are there is row 16 is 65.
In Arithmetic Progression, the difference between two different arithmetic orders is a fixed number (AP). Arithmetic Sequence is another name for it.
We'd come along through a few specific terms in AP that had been labeled as:
As shown below, the AP can also be referred to in terms of common differences.
Now, as the values given in the question;
There are total 16 rows in the arena.
Thus, n = 16.
There are 20 seats present in row 1.
Consider the first term as 'a₁' = 20.
Similarly, there are 23 seats present at row 2.
Consider 'a₂' = 23 is the second term.
Now, calculate the common difference;
d = a₂ - a₁
Put the values in the 'd'.
d = 23 - 20 = 3.
Now, compute the total number of seats in 16th row bu nth formula.
n-th term: an = a + (n − 1) × d
a₁₆ = a₁ + (n - 1)d
a₁₆ = 20 + (16 - 1)3
a₁₆ = 20 + 45
a₁₆ = 65
Therefore, the total number of seats present in the 16th row is 65.
To know more about the arithmetic progression, here
brainly.com/question/24191546
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