A 2.0 kg object which is applied a 4.0 n force will travel 1.0 m in 1.0 seconds
To solve this exercise the formula for net force and the formula for uniformly varied rectilinear motion (UVRM) to be applied are:
- F = m * a
- x = vi * t + (a * t²) / 2
Where:
- F = Force
- m = mass
- a = acceleration
- vi = initial velocity
- x = distance
- t = time
Information about the problem:
- m = 2.0 kg
- vi = 0 m/s
- t = 1 s
- F = 4.0 N
- a = ?
- x = ?
- N = kg * m/s²
Applying the net force formula and isolating the acceleration, we get:
F = m * a
a = F/m
a = 4.0 kg * m/s² / 2.0 kg
a = 2.0 m/s²
Applying the formula for UVRM we can calculate the distance:
x = vi * t + (a * t²) / 2
x = 0 m/s * 1 s + (2.0 m/s² * (1 s)²) / 2
x = (2.0 m/s² * 1 s² / 2
x = 2.0 m/ 2
x = 1.0 m
What is force?
It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.
Learn more about force at: brainly.com/question/12970081
#SPJ4
