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The Isotope calcium-41 decays Into potassium-41, with a half-life of 1.03 x 105 years. There is a sample of calcium-41 containing 5 x 10⁹ atoms.
How many atoms of calcium-41 and potassium-41 will there be after 4.12 x 105 years?
OA 3.125 x 108 atoms of calcium-41 and 4.375 x 10⁹ atoms of potassium-41
OB. 6.25 x 108 atoms of calcium-41 and 4.6875 x 10° atoms of potassium-41
OC. 6.25 x 108 atoms of calcium-41 and 4.375 x 109 atoms of potassium-41
OD. 3.125 x 108 atoms of calcium-41 and 4.6875 x 10° atoms of potassium-41
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Respuesta :

The correct answer for this question will be option D.

Calcium-41 = 3.12×[tex]10^8[/tex] atoms

Potassium-41 = 4.69×[tex]10^9[/tex] atoms

As stated in the question,

Half life of isotope of Ca-14 which decays into K-14 = 1.03 × [tex]10^5[/tex] years

Therefore, after 1.03 × [tex]10^5[/tex] years (1 half life)

Ca-41 will be 50%

and, K-41 will be 50%

After 2.06 × [tex]10^5[/tex] years (2 half lives)

Ca-41 will be 25%

K-41 will be 75%

After 3.09 × [tex]10^5[/tex] years (3 half lives)

Ca-41 will be 12.5%

K-41 will be 87.5%

After 4.12 × [tex]10^5[/tex] years (4 half lives)

Ca-41 will be 6.25%

K-41 will be 93.75%

After 4.12 × [tex]10^5[/tex] years,

Ca-41 = 6.25/100 × 5×[tex]10^9[/tex]

= 3.12 × [tex]10^8[/tex] atoms

K-41 = 93.75/100 × 5×[tex]10^9[/tex]

= 4.69 × [tex]10^9[/tex] atoms

Therefore, option D is correct.

Learn more about half-lives here:

https://brainly.com/question/16387602

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