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Niobium (nb) has a bcc crystal structure, an atomic radius of 0.143 nm, and an atomic weight of 92.91 g/mol. compute and compare its theoretical density with the experimental value.

Respuesta :

Both the theoretical density and experimental value is 8.57g/cm3

The term crystal structure, in crystallography, denotes that the structure in which the atoms (ions or molecules) are attached are arranged in an ordered manner. The smallest repeating unit of the crystal structure is called a unit cell.

Given that:

The radius of Nb is given as R=0.1430nm

The density of Nb is given as d=8.57g/cm3

The atomic weight of Nb is given as M=92.91g/mol

Also, given that the structure is BCC.

The value of the number of atoms per unit cell in BCC is Z=2

The formula for the edge length of BCC structure is,

a=4R/(√3)

Substitute the given values

a=(4*0.1430 nm)/(√3)

=3.3024×10−8cm

The formula for the density of the Nb in BCC structure is,

d2=(Z×M)/(a3×NA)

Substitute the given values.

d1=(2×92.91g/mol)/((3.3024×10-8cm)3 × 6.022 × 1023 mol-1)

=(185.82g/mol)/(21.68cm3/mola3×NA)

=8.57g/cm3

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