The number of oxygen atoms present in H2SO5, C6H10O, Co(NO3)2, and Mg(OH)2 is 5, 1, 6, and 2 respectively.
The subscript located under the element symbol indicates the number of atoms present in the formula; of that element.
In H2SO5, the subscript is 5, so 5 oxygen is present in it.
In C6H10O, there is no subscript, which means there is only 1 oxygen atom present in this formula.
In Co(NO3)2 the subscript of NO3 is 2. So there are 2 molecules of NO3 present in the formula. Also, the subscript of O in NO3 is 3, so there is 3 oxygen in each NO3. In total, the number of oxygen atoms present in Co(NO3)2 is 2×3=6. So 6 oxygen atoms are present in it.
In Mg(OH)2 the is no subscript in OH, so 1 oxygen is present in each OH. there are 2 OH present in the formula, so the total number of oxygen atom present is 2×1=2.
Therefore, 5, 1, 6, and 2 oxygen atoms are present in H2SO5, C6H10O, Co(NO3)2, and Mg(OH)2.
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How many oxygen atoms are present in each of the formulas? H2SO5, C6H10O, Co(NO3)2, and Mg(OH)2.
