The % yield of this reaction is 31.95%
Given:
Mass of C = 9.90g
Actual yield of CO2 (AY) = 11.6g
To Find:
% yield = ?
Formula:
% yield = (actual yield / theoretical yield) x 100
Calculations:
C + O2 –> CO2
mols C = mass C (g) / atomic mass C (g/mol)
mols C = 9.90 / 12 = 0.825 mols
mols CO2 = 0.825 since 1 mol CO2 for each mol C.
Theoretical CO2 yield = mols CO2 x molar mass CO2
TY = 0.825 x 44.01
TY = 36.308g
% yield = (AY / TY) x 100
% yield = (11.6 / 36.308) x 100
% yield = 31.95%
Result:
31.95% is the yield of CO2 in this reaction.
Learn more about % yield here:
https://brainly.com/question/22564628
#SPJ4
