To express of an electron we have to figure out the relationship between momentum and wavelength:
λ= [tex]\frac{h}{p}[/tex] =[tex]\frac{h}{mv}[/tex]
So, velocity of an electron will be:
v= me/λ[tex]e[/tex]h
h= Planck's constant
[tex]m_{e}[/tex] = mass of the electron
Now we will see what is its value:
V= h/mcλ
[tex]\frac{6.626 .10^{-34}J.s}{(9.109.10^{-31}kg).(100.10^{-12m)} }\\ 7.27.10^{6} m.s^{-1}[/tex]
Now, to express accelerating potential energy difference we will use kinetic energy and charge of electron
Kinetic energy: [tex]E_{K} =e_{E}[/tex]
But kinetic energy in terms of velocity is
:[tex]\frac{(9.109.10^{-31}kg).(7.27.10^{6}ms^{-1})^{2} }{2.(1.602.10^{-19} C)} \\=150.210^{-31} .10^{-31} .10^{12}.10^{19}V \\ = 1.502.10^{2}V[/tex]
To know more about kinetic energy visit:
https://brainly.com/question/12669551
#SPJ4