Her resultant displacement is 5 blocks.
Her net x (east-west) displacement is –3.00+0+6.00= +3.00 blocks, while her net y (north-south) displacement is 0+4.00+0=+4.00 blocks.
The magnitude of the resultant displacement is
R= [tex]\sqrt{x^{2} +y^{2} } =\sqrt{3^{2} + 4^{2} }[/tex] = 5 blocks
and the angle made by the resultant
= [tex]\theta[/tex] = [tex]tan^{-2} =[/tex] 4/3
= 53.1°
The resultant displacement is 5 blocks at 53.1°
The term “displacement” refers to a shift in an object’s position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place.
For instance, if an object shifts from location A to position B, its position changes.
An object’s displacement is equal to its velocity times its acceleration times its time squared plus one-half (t2).
A scalar quantity known as distance measures “how much ground an object has traversed” while moving.
The term “how far out of place an object is” is referred to as displacement, a vector quantity.
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