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MrRoyal

The value of x is 14 and the measure of angle J s 103

How to solve for x and the measure of angle J?

The given angles are external angles of parallel lines and a transversal

So, we have:

6x - 7 + 7x + 5 = 180

Evaluate the like terms

13x = 182

Divide both sides by 13

x = 14

Substitute x = 14 in J = 7x + 5

J = 7 x 14 + 5

Evaluate

J = 103

Hence, the value of x is 14 and the measure of angle J s 103

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The values of x and angle J are 14 and 103 degrees respectively.

How to determine the angle

It is important to note that angles on a transversal line are supplementary, that is, they sum up to 180 degrees

Given the angles as;

  • 6x - 7
  • 7x + 5

Equate the angles

6x - 7 + 7x + 5 = 180

collect like terms

6x + 7x = 180 +2

13x = 182

Make 'x' the subject

13x/ 13 = 182/ 13

x = 14

But angle J = 7x + 5 = 7(14) + 5 = 98 + 5 = 103

Thus, the values of x and angle J are 14 and 103 degrees respectively.

Learn more about supplementary here:

https://brainly.com/question/12919120

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