√3+ √11 is greater than 5 .
We first assume that √3+ √11 is greater than 5. Then we check if our assumption is correct.
So suppose that √3+ √11 > 5
Squaring on both sides and using the identity [tex](a+b)^2=a^2+b^2+2ab[/tex],
⇒ 14 + 2√33 > 25
Subtracting 14 from both sides,
⇒ 2√33 > 11
Again squaring,
⇒ 132 > 121
This is a true statement. So our assumption that √3+ √11 is greater than 5 is right.
Therefore, √3+ √11 > 5
Learn more about irrational numbers at https://brainly.com/question/5023447
#SPJ4
