Answer:
[tex]\frac{4}{10} =\frac{3.2}{8}[/tex]
Step-by-step explanation:
Given : AD=4
DB=6
AE=3.2
EC=4.8
AB=10
AC=8
Solution :
Theorem :A transversal that is parallel to one of the sides in a triangle divides the other two sides proportionally.
So,
[tex]\frac{AD}{AB} =\frac{AE}{AC}[/tex]
[tex]\frac{4}{10} =\frac{3.2}{8}[/tex]
[tex]\frac{4}{10} =\frac{32}{80}[/tex]
Reduce the fraction both sides by dividing both the fractions with common factor respectively.
[tex]\frac{2}{5} =\frac{2}{5}[/tex]
Thus ans in boxes will be [tex]\frac{4}{10} =\frac{3.2}{8}[/tex]
This verify that BC ∥ DE.
