[tex]x-4~\geqslant~-1\implies x~\geqslant~-1+4\implies \boxed{x~\geqslant~3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{multiplying both sides by -5}}{-5(x)\underset{\stackrel{\uparrow }{notice}}{~\leqslant~}-5(3)}\implies -5x~\leqslant~-15\implies -5x= \begin{cases} -15 ~~ \textit{greatest value}\\ -16,-17,-18...-\infty \end{cases}[/tex]
let's recall that for inequalities whenever we divide or multiply or exponentialize by a negative value, we must flip the inequality sign, notice, multiplying by -5, flipped it sideways.
Also let's recall that on the negative side of the number line, the closer to 0, the greater, thus -1 is much much greater than -1,000,000.
