The product of (4+2√3)(6-3√3) is 15.
1. Divide the radicands by two. Under the radical sign, there is a number called a radicand. 2. Multiple the integers as though they were whole numbers in order to multiply radicands. Keep the product under a single radical sign at all times.
3. Remove any perfect squares from the radicand by factoring. Check to determine whether the radicand is a factor of any perfect squares to do this.
4. Before the radical sign, place the square root of the ideal square. Keep the second element in the radical sign.
5. Square the root of a square. A square root may occasionally need to be multiplied by itself.
(4+2√3)(6-3√3)
⇒ 4 ×6 + 4 × -3√3 + 2√3 × 6 - 2√3 × 3√3
⇒ 24 - 12√3 + 12√3 - 9
⇒ 15
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