Answer: B. [tex]38\ in^2[/tex]
Step-by-step explanation:
Area of a rectangle with dimension " l by w" is given by :-
[tex]A_r=l\times w[/tex]
Area of square with dimension "a by a" is given by :_
[tex]A_s=(a)^2[/tex]
Now Using (1), Area of rectangle with dimension 9-inch by 6-inch will be :-
[tex]A_r=9\times 9=54\ in^2[/tex]
Using (2), Area of square with dimension 4-inch by 4-inch will be :-
[tex]A_s=4^2=16\ in^2[/tex]
Now, the required area = [tex]A_r-A_s=54-16=38\ in^2[/tex]
Hence, B is the correct option.
