contestada

Sean’s age and Helen’s age are in the ratio of 3:5. Two years ago, Helen was twice as old as Sean was then. Find their present ages.

Respuesta :

Lets Sean's age be x
Helen's age by y
x/y=3/5
x=3/5y

Second equation
2(x-2)=y-2

on solving u get Helen as 10 and Sean as 6
aksnkj

The present age of Sean is 6 years and the present age of Helen is 10 years.

Given,

The ratio of Sean's age and Helen's age is 3:5.

Let the present age of Sean be [tex]3x[/tex] years and the present age of Helen be [tex]5x[/tex] years.

So two years ago,

Helen's age was [tex](5x-2)[/tex] years and Sean's age was [tex](3x-2)[/tex] years.

According to the question, Two years ago,

Helen was twice as old as Sean was then.

How to write linear equations?

So in equation form, we get

[tex](5x-2)=2(3x-2)[/tex]

[tex]5x-2=6x-4[/tex]

[tex]x=2[/tex].

So, the present age of Sean will be [tex]3\times2 =6[/tex] years.

The present age of Helen will be [tex]5\times2=10[/tex] years.

For more details about linear equations, follow the link:

https://brainly.com/question/22048320

Otras preguntas