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Which equilibrium system least favors the formation of products?
2HgO(s) 2Hg(l) + O2(g) Keq = 1.2 x 10-22
CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO- (aq) Keq = 1.8 x 10-5
2NO(g) + O2(g) 2NO2(g) Keq = 6.5 x 105
2(g) + Cl2(g) 2HCl(g) Keq = 1.8 x 1033

Respuesta :

AISstudent
It's the first one
since Keq is really low , which means reaction won't take place at all and would favor the reactions

Reaction proceeds to the left

The equilibrium system least favors the formation of products of 2HgO(s) 2Hg(l) + O2(g) Keq = 1.2 x 10-22.

What is equilibrium?

Chemical equilibrium occurs when both reactants, as well as products, as well as products, are present in concentrations that really have no further capability to affect with time, resulting in no discernible change in the system's properties.

It is given that.

a) 2HgO(s) 2Hg(l) → O2(g) Keq = 1.2 x 10-22

b) CH3COOH(aq) + H2O(l) → H3O+(aq) + CH3COO- (aq) Keq = 1.8 x 10-5

c) 2NO(g) + O2(g) → 2NO2(g) Keq = 6.5 x 105

d) 2(g) + Cl2(g) → 2HCl(g) Keq = 1.8 x 1033

It can be seen that 2HgO(s) 2Hg(l) → O2(g) posses lowest equilibrium constant (Keq )value. As the value equilibrium constant( Keq) value of the reaction decreases the formation of product is also decreases.

Therefore, the correct answer will be option (a).

To know more about equilibrium.

https://brainly.com/question/13463225

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