a) Cross: Tt × tt
Offspring: Tt, Tt, tt, tt
1) Phenotypic ratio: Long: Stem = 2:2 = 1:1
2) Genotypic ratio: TT : Tt : tt = 0 : 2 : 2
b) Cross: Tt × Tt
Offspring: TT, Tt, Tt, tt
1) Phenotypic ratio: Long: stem = 3 : 1
2) Genotypic ratio: TT : Tt : tt = 1 : 2 : 1
4) Cystic fibrosis is regulated by a recessive allele, it means, it would be "Active" when both the allele will be same in the Offspring. So, let father transmits "Y" chromosome to his son, and mother "X" if they both were carrier of this disease, then they will inherit it to their offspring.
Genotype: XcXc or XcY
Hope this helps!